2,5x^2=2800

Solution for 2,5x^2=2800 equation:

2.5x^2=2800

We move all terms to the left:

2.5x^2-(2800)=0

a = 2.5; b = 0; c = -2800;
Δ = b2-4ac
Δ = 02-4·2.5·(-2800)
Δ = 28000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28000}=\sqrt{400*70}=\sqrt{400}*\sqrt{70}=20\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{70}}{2*2.5}=\frac{0-20\sqrt{70}}{5}
=-\frac{20\sqrt{70}}{5}
=-4\sqrt{70}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{70}}{2*2.5}=\frac{0+20\sqrt{70}}{5}
=\frac{20\sqrt{70}}{5}
=4\sqrt{70}
$